A play school has chocolates which can supply 50 students for 30 days. For the first ten days only 20 students were present. How many more students can be accommodated into the earlier group such that the entire chocolates get consumed in 30 days. Assume each student takes the same number of chocolates. a. 45 b. 60 c. 55 d. 70

Let each students gets 1 chocolate. Now total chocolates = 50 x 30 = 1500 If first 10 days only 20 students were present, then total chocolates consumed = 10 × 20 = 200 Now we are left with 1500 - 200 = 1300 chololates. These were to be consumed in 20 days. So each day 1300/20 = 65 chocolates were to be distributed. So we can add 65 - 20 = 45 students.