-1


A pair of 8 slided dice has sides numbered 1 to 8. Each side has same probability or chance of landing face up. The probability that the product of 2 numbers on the sides that land face up exceeds 36 is
a)11/64 b)5/32 c)3/16 d)1/4
Asked in/Preparing for : tcs


1 Respond


There are `8` times `8 = 64` combinations to examine.
 
If one die is `1` , then even with an `8` on the other die, no combinations will work.
 
If one die is `2` , then even with an `8` on the other die, no combinations will work.
 
If one die is `3` , then even with an `8` on the other die, no combinations will work.
 
If one die is `4` , then even with an 8 on the other die, no combinations will work.
 
If one die is `5` , then the other die must be an `8` to have a product over `36` . Thus, `(5,8)` works.
 
If one die is `6` , then the other die must be either `7` or `8` to have a product over 36. Thus, `(6, 7)` and `(6, 8` ) both work.
 
If one die is `7` , then the other die can be `6` , 7, or `8` to have a product over `36` . Thus, `(7, 6), (7, 7)` , and `(7, 8)` all work.
 
If one die is `8` , then the other die can be 5, 6, 7, or `8` to have a product over `36` . Thus, `(8, 5), (8,6), (8,7),` and `(8,8)` work.
 
There are a total of `1 + 2 + 3 + 4 = 10 ` combinations that work out of a total of `64` possibilities.
 
Thus, the answer is `10/64 = 5/32`

Admin Team



Written
Exam Questions
BLOG Posts
For study materials
Job Walk-In
Updates across India
Interview round
Questions
Interview or procedure
Experiences
Files
For study materials
Please LIKE our page to Get regular JOB WALK-IN UPDATES across India and STUDY MATERIALS on facebook news feed.